45.跳跃游戏Ⅱ

贪心

时间复杂度$O(n)$

空间复杂度$O(1)$

class Solution {
    public int jump(int[] nums) {
        int ans = 0, n = nums.length, right = 0, newRight = 0;
        for (int i = 0; i < n; ++i) {
            if (right >= n - 1) {
                break;
            }
            newRight = Math.max(newRight, i + nums[i]);
            if (i == right) {
                right = newRight;
                ans++;
            }
        }
        return ans;
    }
}